Question

I need some help with eccentricity.
The question will be posted in the comments..
I know e = c/a
How do I find c?

Answer 1

\[\large \frac{ (x-5)^2 }{ 8 } + \frac{ (y+1)^2 }{ 12 } = 1\]

Answer 2

b^2 + c^2 = a^2
a^2 = 12
a = 2√3
b^2 = 8
b = 2√2
8 + c^2 = 12
c^2 = 4
c = 2
so..
e = 2/2√3
e = 1/√3
right?

Answer 3

a = major axis
b = minor axis

so looks in ur calucaltion, u have reversed them

Answer 4

oh no, you're right ! i overlooked it ...

Answer 5

the major axis is equal to 2a.
minor axis is equal to 2b.
and a^2 is always the bigger one of the two denominators.. atleast that's what i read ..

Answer 6

yes ! looks good

Answer 7

thanks.

Answer 8

np :)