Question

GIVING MEDALS!!! Isosceles Trapezoid ABCD has diagonals AC=10x+7 and BD = 2x+41. Find The Value Of x. :D

Answer 1

the diagonals in an Isosceles Trapezoid would be equal
therefore AC = BD
and so solve for x when 10x + 7 = 2x + 41

Answer 2

4.5?

Answer 3

close, I'm getting 4.25

Answer 4

No wait.

Answer 5

Yeah, I got it :D

Answer 6

If one base angle of an isosceles triangle measures 42 Degrees, what is the measure of the other base angle? :D

Answer 7

42? Correct?

Answer 8

Correct! :D

Answer 9

the parallel line transversal thing (I forgot the name of it)

Answer 10

?

Answer 11

because of that rule, you can get that
(5x + 13) + (3x - 5) = 180

Answer 12

ik xD I got it :P

Answer 13

21.5?

Answer 14

correct! :)

Answer 15

Thank you? Can You Do more?

Answer 16

of course :)

Answer 17

If the length of one base of a trapezoid is 5, the length of the other base is 2x + 7, and the length of the midsegment is 6x-24, what is the value of x?

Answer 18

the midsegment is the average of the two bases so
\[\frac{ (5) + (2x + 7) }{ 2 } = (6x - 24)\]

Answer 19

I don't know how to find that :/

Answer 20

multiply both sides by 2
so (5 + 2x + 7) = 2(6x - 24) then distribute

Answer 21

@jigglypuff314

Answer 22

Can you help?

Answer 23

If the length of one base of a trapezoid is 5, the length of the other base is 2x + 7, and the length of the midsegment is 6x-24, what is the value of x?

Answer 24

I've already gone over the first few parts of it above...
solve for x when 2x + 12 = 12x - 48

Answer 25

x=6? @jigglypuff314

Answer 26

sorry it took me so long, I had a class to go to,
x = 6 would be correct :)