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Mathematics 11 Online
OpenStudy (anonymous):

thx

OpenStudy (raden):

first, setting 1 = log 10

OpenStudy (raden):

now we have the equation : 2 log x = log(2x-10) + 1 2 log x = log(2x-10) + log 10

OpenStudy (raden):

then use the properties of log to simplify both sides, get 2 log x = log(2x-10) + log 10 log x^2 = log 10*(2x-10)

OpenStudy (raden):

and if given log a = log b, then a = b. therefore : if log x^2 = log 10*(2x-10), then x^2 = 10*(2x-10) x^2 = 20x - 100 solve for x

OpenStudy (anonymous):

got this, but why do i have to set 1 to log 10? Thanks or helping by the way:)

OpenStudy (raden):

see the bases of log x^2 and log (2x-10) is 10, right ?

OpenStudy (anonymous):

Yes, oh god you saved me thanks a lot!

OpenStudy (raden):

you're welcome :)

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