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first, setting 1 = log 10
now we have the equation : 2 log x = log(2x-10) + 1 2 log x = log(2x-10) + log 10
then use the properties of log to simplify both sides, get 2 log x = log(2x-10) + log 10 log x^2 = log 10*(2x-10)
and if given log a = log b, then a = b. therefore : if log x^2 = log 10*(2x-10), then x^2 = 10*(2x-10) x^2 = 20x - 100 solve for x
got this, but why do i have to set 1 to log 10? Thanks or helping by the way:)
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see the bases of log x^2 and log (2x-10) is 10, right ?
Yes, oh god you saved me thanks a lot!
you're welcome :)
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