Question

Find the horizontal and vertical asymptote of (x-2)^2(x+1)
Is there no horizontal asymptote and would the vertical asymptote be -1, and 2?

Answer 1

Well remember that a vertical asymptote means that the function is undefined at that point...so there is no vertical asymptote here

Answer 2

So is there neither horizontal nor vertical?

Answer 3

Is there no vertical and no horizontal*

Answer 4

That would be correct!

Vertical asymptote occurs when a denominator is present and that denominator = 0
Horizontal asymptotes occur when you see what this function will = when x = infinity. so if we do this here...we get infinity ...so no horizontal asymptote...
There would be a slant asymptote but since the question didnt state it, I wouldnt worry about it.

Answer 5

Do I only see when it will occur at x= infinity if it has a denominator? I remember there was a rule like 3x-4 / 4x-4 = 3/4 because of the degrees?