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Mathematics 9 Online
OpenStudy (yacoub1993):

Graph the solution set of the system of inequalities or indicate that the system has no solution. y ≥ 2x – 4 x + 2y ≤ 7 y ≥ -2 x ≤ 1

OpenStudy (yacoub1993):

OpenStudy (yacoub1993):

@Directrix Help me Please

Directrix (directrix):

@Yacoub1993 Is the task to graph the solution set of all four of the inequalities posted in the problem?

OpenStudy (yacoub1993):

I dont know what to do could you help me out with it

Directrix (directrix):

I asked you above if all four inequalities are drawn on one set of axes? It looks that way. In other words, this is not 4 separate problems.

Directrix (directrix):

At the moment, I am looking for a point that makes all 4 inequalities true and then we will look at options to see if that point is shaded. We may have to draw the graphs. We'll see.

Directrix (directrix):

@Yacoub1993 Are you ready to work with me?

OpenStudy (yacoub1993):

yes i am ready

Directrix (directrix):

(-2,0) is a point I found that satisfies all four of the inequalities given. That means that (-2,0) should be part of the shaded region of the correct option.

Directrix (directrix):

Click on the first option. Find the point (-2,0) on the graph of the first option. Is the point (-2,0) shaded in that first option? Or, is the point (-2,0) out in the white background? Tell me what you think while I look at it, too.

OpenStudy (yacoub1993):

ok wait

OpenStudy (yacoub1993):

the second one right

OpenStudy (yacoub1993):

the shaded one

Directrix (directrix):

Look at the first option. I have attached the kind of thing we are doing so that you can understand. Don't look at the second option yet. Look at the attachment.

Directrix (directrix):

I located the point (-2, 0) in the first option, marked it, and noticed that it was not in the shade. So, option one is not the correct answer.

OpenStudy (yacoub1993):

yes option one is not shaded

Directrix (directrix):

The reason we are using the point (-2,0) is that is makes all four of the given inequalities true. y ≥ 2x – 4 x + 2y ≤ 7 y ≥ -2 x ≤ 1

Directrix (directrix):

So, now look at option 2 and find the point (-2,0) and see if it is shaded. Please do not look at option 3 yet. :)

OpenStudy (yacoub1993):

yes option 2 is shaded

Directrix (directrix):

Yes. So, option 2 is a contender but it could still be the *wrong option*. We have to test another point. So put option 2 on hold. Let's go to option 3 and see if we can eliminate it from the running.

Directrix (directrix):

Option 1 is out. Option 2 is still in the running. Now, test option 3.

Directrix (directrix):

What did you get for option 3?

Directrix (directrix):

@Yacoub1993 ^^^^

Directrix (directrix):

We're down to option 2 or option 3 as being correct.

OpenStudy (yacoub1993):

option 3 is also shaded.... sory for late reply

Directrix (directrix):

And, 4 is not.

OpenStudy (yacoub1993):

option 4 is not shaded so that one is also out its between option2 and option3

Directrix (directrix):

To decide between options 2 and 3, we will test the point (-8,7). That point makes all 4 inequalities true so it should be shaded. This won't be so tedious. :) Look for (-8,7) to see if it is shaded on option 2 and then option 3.

OpenStudy (yacoub1993):

i am sure it will be C

OpenStudy (yacoub1993):

i am sure it will be the third

Directrix (directrix):

Me, too. These inequalities are so tedious. But, we did it.

OpenStudy (yacoub1993):

thnxs @Directrix

Directrix (directrix):

You are welcome.

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