Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (lena772):

Functions help.

OpenStudy (lena772):

hero (hero):

@Lena772, the slope of g(x) is already given, right?

hero (hero):

And to find the slope of f(x), we just need to take two points and apply the slope formula \(m = \dfrac{y_2 - y_1}{x_2 - x_1}\)

OpenStudy (the_fizicx99):

PART A: f(x): -5 - - 1 = -4 -1 - 0 = -1 f(x): 4 g(x): mx + b = y; m is the slope therefore in the g(x) equation 4 is the slope. Both functions have the same slope of 4. PART B: f(x): y - y1 = m (x-x1) y- (-5) = 4(x - (-1)) y + 5 = 4x + 4 - -5 y= 4x - 1 g(x)= 4x + 3, thus accordingly with the formula mx+b, b being the y-intecept. The y intercept of this function is 3. g(x) has a greater y-intercept than f(x). Is that what they're asking for?

OpenStudy (lena772):

but i dont think you calculated the slope right for f(x)

OpenStudy (lena772):

cuz i got -6

OpenStudy (the_fizicx99):

where

OpenStudy (the_fizicx99):

You mean here : y + 5 = 4x + 4 - 5 -5 ?

OpenStudy (lena772):

PART A: The slope of g(x)=4. (given) m=y2-y1/x2-x1 f(x)=y -1-5/0--1 -6/1 m=-6 The slope of f(x)=-6 PART B: The y intercept of g(x) is 3. (given) f(x)=-6x+b -5=-6*-1+b -5=6+b -11=b The y intercept of g is bigger.

OpenStudy (the_fizicx99):

O.o ohh you mean cus its negative?

OpenStudy (lena772):

no I mean because when I calculate the slope of f(x) i don't get 4

OpenStudy (the_fizicx99):

xD -5- (-1) negative and negative is positive

hero (hero):

\((x_1, y_1) = (0,-1)\) \((x_2, y_2) = (-1,-5)\) \[m = \frac{y_2 - y_1}{x_2 - x_1}\] \(m = \dfrac{-5 - (-1)}{-1 - 0} = \dfrac{-5 + 1}{-1} =\dfrac{-4}{-1} = 4 \)

OpenStudy (the_fizicx99):

Ty @Hero

OpenStudy (lena772):

Lol thanks!

OpenStudy (the_fizicx99):

Yw :3

OpenStudy (skullpatrol):

@Lena772 have you seen the Khan Academy videos?

OpenStudy (the_fizicx99):

There's a help site in the announcement page, there's links to Khan and help sheets :D

OpenStudy (lena772):

I've seen a few actually. I find them to be a waste of time. The guy just rambles. I rather get help on OS

OpenStudy (the_fizicx99):

*storms out w/o medals* >.<'

OpenStudy (skullpatrol):

He tries to teach more for understanding than learning, but if you stay with his program you will get great results.

OpenStudy (the_fizicx99):

Yeaa, the point is to clarify doubts/how to's not to learn an entire lesson though

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!