Question

help?!?!?!

Answer 1

wow let me see what i can see to help : )

Answer 2

Factor out numerator and denominator starting from the top and then do the bottom and cross out like terms

Answer 3

can you factor \(\bf x^2-4x-32 \ and \ 6x^2-6x-12\quad ?\)

Answer 4

keep in mind that \(\bf 6x^2-6x-12\implies 6(x^2-x-2)\)

Answer 5

so try first simplifying \(\bf x^2-4x-32 \quad \textit{and}\quad 6(x^2-x-2)\)

Answer 6

Step 1 :

Multiply 12x-96 by x2-4x-32
Pulling out like terms :

1.1 Pull out like factors:

12x - 96 = 12•(x - 8)
Trying to factor by splitting the middle term

1.2 Factoring x2 - 4x - 32

Method : Factoring by splitting the middle term

The first term is x2 ,its coefficient is 1
The middle term is -4x ,its coefficient is -4
The last term, also called 'the constant', is -32

Step-1 : Multiply the coefficient of the
first term by the constant

1 • -32 = -32

Step-2 : Find two factors of -32 whose
sum equals the coefficient of the
middle term, which is -4

-32 + 1 = -31
-16 + 2 = -14
-8 + 4 = -4 Tiger found it !!

Step-3 : Rewrite the polynomial splitting
the middle term using the two
factors found in Step-2, (-8) and (4)

x2 - 8x + 4x - 32

Step-4 : Add up first 2 terms, pulling
out like factors : x•(x-8)

Add up last 2 terms, pulling
out common factors: 4•(x-8)
———————————
Factorization is : (x+4)•(x-8)

Answer 7

i hope this helped

Answer 8

is it b then?

Answer 9

the answer is (a)