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OpenStudy (anonymous):
x+y-z=5
2x-y+3z=-3
2x+3y=-4
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OpenStudy (anonymous):
could you help me out, kelligirl?
OpenStudy (anonymous):
you writing down the problem to go over it step by step with me?
OpenStudy (anonymous):
i think she is writing the whole solution!
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
x + y - z = 5 ---->(3)
2x - y + 3z = -3
--------------
3x + 3y - 3z = 15 (result of multiplying by 3)
2x - y + 3z = -3
--------------add
5x + 2y = 12
2x + 3y = -4 -->(-2)
5x + 2y = 12 -->(3)
----------------
-4x - 6y = 8 (result of multiplying by -2)
15x + 6y = 36 (result of multiplying by 3)
-----------------add
11x = 44
x = 44/11
x = 4
2x + 3y = -4
2(4) + 3y = -4
8 + 3y = -4
3y = -4 - 8
3y = -12
y = -12/3
y = -4
x + y - z = 5
4 - 4 - z = 5
-z = 5
z = -5
check...
x + y - z = 5
4 - 4 -(-5) = 5
0 + 5 = 5
5 = 5 (correct)
x = 4, y = -4, z = -5
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
but
OpenStudy (anonymous):
ehh
OpenStudy (anonymous):
wait
OpenStudy (anonymous):
if you have any questions, please ask
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OpenStudy (anonymous):
oh yes
OpenStudy (anonymous):
I should have said: solve the equation using Cramer's rule
OpenStudy (anonymous):
like this
OpenStudy (anonymous):
|dw:1385828430235:dw|
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