Question

Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).



A.) y = 1/3x − 3

B.) y = 1/3x + 17

C.) y = −3x − 3

D.) y = −3x + 17

Answer 1

Can you find the slope of the line that you are given?

Answer 2

I found it by putting 3x+y=7 into y=mx+b form.

Answer 3

y=7-3x
here , b= 7 and m= -3
but we know that in perpendicular position we use m1m2=-1
m -3 =-1
m=1\3
so m=1\3
and the line passes from the (6,-1)
(x,y)=(6,-1)
y=mx+b
-1=6(1\3)+b
-1= 2+b
b=-1-2
b=-3
now put it in the slope intercept from
y=1\3 x -3
this is the true answer

Answer 4

A is the correct answer
A) y=1\3 x -3