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64=(x+8)^3/2 find x
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This problem is a simple algebra problem, so we simply follow the rules of PEMDAS. Given: (x+8)^(3/2)=64 find x We take everything raised to the 2/3 because that will eliminate the ^(3/2) above (x+8) This gives us: (x+8)=(64)^(2/3) 64 raised to the 2/3 would be the same as if you squared 64 which would be 4096, and then took the 3rd root of that. This computation leaves us with 16. Now we have: x+8=16 Subtract 8 from each side, and you get x=8. Check: When we plug 8 in for x we get, (8+8)^(3/2)=64 64=64 We now know that we are correct. Hope this helps!!
sweet thanks a lot! i was stuck on the 3rd step
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