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(x+3^(1/3()(x-3^(1/3))/(x-27) as limit x approaches 27.find the limit.
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\[\lim_{x\to27}\frac {(x+3^{1/3})(x-3^{1/3})}{x-27}\]correct?
yes
are you sure you typed that correctly? none of the x's are squared or cubed or anything?
no.i misprint it .The 1/3 will be over x,not over 3.
that makes much more sense\[\lim_{x\to27}\frac {(x^{1/3}+3)(x^{1/3}-3)}{x-27}\]
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factor the denominator using difference of cubes
\[a^3-b^3=(a-b)(a^2+ab+b^2)\]
yes i am doing.
ok, let me know if/where you get stuck
yes,i got the answer 2/9,thank you very much.
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you're welcome :)
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