How do you find the effort(NEWTONS) in a CLASS-1 lever? Any formula will surely help.

Question

anonymous · Answer

Since it is in newtons, it is force. Your torque, force times length of lever arm to the fulcrum, F d, balances the object's weight times its distance from the fulcrum, W (L-d), for a lever of length L. Your mechanical advantage, your "leverage," is d/(L-d) the ratio of the two "lever arms."
The inverse of this is the force you need to lift the weight. If "effort" is the work done, the lever does not change this, as you move your side the longer distance by the inverse of this ratio in raising the weight by h.

calculusxy · Answer

@douglaswinslowcooper Can you give me an example?