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The tangent line to the graph of y=h(x) at the point (-1,4) passes through the point (3,6). Find h(-1) and h'(-1).
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Since y = h(x), and (-1, 4) is a point that lies of the curve h(x), we know that h(-1) = 4. We know that the tangent line that passes through (-1,4) on h(x) also passes through the point (3,6). The find h'(-1), simply find the slope of the line that passes through (-1,4) and (3,6).
*To find h'(-1)...
Its 1/2
Yes it is.
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