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completely factor 4x^3+36x^2+4x+36
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I know it is going to have 4(x^3+9x^2+x+9) for the next step. Is that completely factored?
Nope, finish by factoring by grouping.
x^3+x and 9x^2+9 ?
I think it would be better if we left that 4 back into the equation
4(x^3+x)(9x^2+9) ?
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Not exactly: |dw:1385963722885:dw| Make sense?
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