This is in slope intercept form and is parallel to the line y=-5x-3 and goes through the y-axis at -4. How would I do that? Thanks!

Question

alekos · Answer

So the new line goes thru y=-4 and is parallel to y=-5x-3, so it's slope will also be -5
Hence the new line would have an equation y=mx+b where m(the slope)=-5 and b(the y-intercept) is -4

jonnyvonny · Answer

Now, to make a function parallel to another, all you do is keep the same slope (#x), but change the constant (the number being added or subtracted to x). Now, they told you the y-intercept, which is when the graph touches the y-axis; this happens when you set x=0. When we set the original function equal to 0, we get -3. Since all we do is change the number being added/subtracted to x, we see that the new function is $$y=-5x-4$$