Question

calc question!

Answer 1

please help!

http://vvcap.net/db/Ek87NWVnJ9NWQB6yNbJZ.htp

Answer 2

so domain.. all real numbers?

Answer 3

heeeeelp

Answer 4

Its not; due to the square root; you cannot find the square root of a negative number.\[2-x^2>0\rightarrow-x^2>-2\rightarrow x^2<2\rightarrow x< \pm \sqrt{2}\] The reason why we don't care about the x on the outside, is because its not RESTRICTING us domain speaking, the square root is, however.

Answer 5

x is less than OR equal to plus or minus sqrt2. It's okay to have the sqrt of 0.

Answer 6

Using calculus means they want you to take the derivative. The function will be decreasing where the derivative is negative. Use the 2nd derivative test and I think it makes the question easier.

Answer 7

@jam333 True, true.