How do i turn a inequality into a point slope form equation and solve it?

Question

solomonzelman · Answer

y=mx+b

put your equation into that form and plug in values for x to graph it.

solomonzelman · Answer

Do you have a specific question?

undeadknight26 · Answer

y ≥ (-2/3)x -3

undeadknight26 · Answer

so is it :
-2/3x -3 = y?

solomonzelman · Answer

No

solomonzelman · Answer

But you can use  -2/3x -3 = y?   to find the points.

solomonzelman · Answer

I am plugging in -3 and -6 for x,
if x=-3 y= -1    so the first coordinate would be (3, -1)
if x=-6 y= 1      so the second coordinate would be (6, 1)

graph it.

solomonzelman · Answer

|dw:1386085200535:dw|

undeadknight26 · Answer

where did u get 6 and 1?

solomonzelman · Answer

and shade the area that is less than y or equal to it (incl to the line)
|dw:1386085295806:dw|

and the points are

if x=-3 y= -1    (3, -1)
if x=-6 y= 1      (6, 1)

I used
y = (-2/3)x -3

to get the points
and then graphed it as
y ≥ (-2/3)x -3
y ≥ meaning that the graph is everything that is less than or equal to that line.

Still lost?