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(x^3*y^1/3)^(-4/5)
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\[\large (x^3y^\frac{ 1}{ 3 })^{-4/5}\] When you multiply exponents like this \[\large a^m * a^n = a^{m+n}\] For this \[\huge (a^n)^m = a^{n*m}\]
ok
Also, \[\huge x^{-n} = \frac{ 1 }{ x^n } \] and for the fraction powers.. \[\huge \sqrt[n]{x^m} = x^{m/n}\]
Can you simplify given these formulas/rules?
can you show me how to do it
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\[\huge (x^3y^{1/3})^{-4/5}\] You get : \[\huge x^{-12/5}y^{-4/15}\] \[\huge \sqrt[5]{x^{-12}} * \sqrt[15]{y^{-4}}\] \[\huge \frac{ 1 }{ \sqrt[5]{x^{12}} } * \frac{ 1 }{ \sqrt[15]{y^{4}} }\]
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