What is the measure of the vertex angle of an isosceles triangle if one of its base angles measures 53° and its congruent sides each measure 15 cm?
What is the measure of the vertex angle of an isosceles triangle if one of its base angles measures 53° and its congruent sides each measure 15 cm?
If you are dealing with an isosceles triangle, if one of the base angles measures 42 degrees then the other base angle measures 42 degrees. (By definitioin an isosceles triangle has at least 2 equal sides and the angle opposite those sides with be equal.) If you add up the degrees in each angle within a triangle, it will always equal 180 degrees. Knowing all this you can set up a formula: Angle 1 + Angle 2 + Angle 3 = 180 42 + 42 + Angle 3 = 180 Angle 3 = 96 degrees
there ya go
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