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Mathematics 15 Online
OpenStudy (anonymous):

Use basic identities to simplify the expression: cot x tan x

OpenStudy (shamil98):

Cotangent is equal to 1/tan So. \[\huge \cot x *\tan x\] \[\huge \frac{ 1 }{ \tan x } * \tan x\] \[\huge \frac{ \tan x }{ \tan x } = 1\]

OpenStudy (jonnyvonny):

^

OpenStudy (anonymous):

cot x sin x @shamil98

OpenStudy (shamil98):

Tan = sin/cos So: \[\huge \frac{ 1 }{ \tan x } * \sin x\] \[\huge \frac{ 1 }{ \frac{ sinx }{ cosx } } * \sin x\] Dividing fractions you multiply by the reciprocal \[\huge \frac{ 1 }{ \sin x } * \cos x * \sin x\] Sin x cancels \[\huge \frac{ 1 }{ \cancel {\sin x} } * \cos x * \cancel {\sin x} = 1 * \cos x \] \[\huge cos x\] is your final answer :)

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