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f(x) = (1/2)^x - 3 How do I graph this? as well as find the domain and range.
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it looks like \(y=\frac{1}{2^x}\) only shifted down 3 units
domain is all real numbers, because you can raise \(\frac{1}{2}\) to any power you like
So, the only way to graph this by a graphing calc/wolfram/online calc?
range is \((-3,\infty)\) because no matter what \(x\) is you know \((\frac{1}{2})^x>0\) and so \[(\frac{1}{2})^x-3>-3\]
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no you don't need wolfram if you have a general idea of what \[y=\frac{1}{2^x}=\left(\frac{1}{2}\right)^x=2^{-x}\] looks like
|dw:1386047251032:dw|
Thank you. Was a bit confused with this. That clarified it.
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