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Factor out a perfect square for 99
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\[b=\sqrt{99}\]
Are you familiar with the list of perfect squares?
1 4 6 etc. ?
not 6 i mean 9
The set of perfect squares are {1, 4, 9, 16...} Of those, choose the one that is most appropriate to factor out.
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I know the list of perfect squares I just struggle with factoring them out
We know \(99 = 9 \times 11\) right? And we know that \(9\) and \(11\) are factors
I thought the factors both had to be perfect squares
Notice it says to factor out "a" perfect square. "a" means "one" so therefore we need at least "one" of the factors to be a square. It didn't say all the factors of 99 had to be a square.
@Hero thank you
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