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Which of the following is the equation of the axis of symmetry of the quadratic equation y = 2x2 + 24x + 62? x = –6 x = 6 x = –10 x = 10
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for a parabola of \(\bf y = ax^2+bx+c\) type, you can always find the vertex at the coordinates of \(\bf \left(-\cfrac{b}{2a}\quad ,\quad c-\cfrac{b^2}{4a}\right)\) so what's the vertex for \(\bf y = 2x^2 + 24x + 62\quad ?\)
a parabola with a squared "x" term, will go either upwards or downwards, so the axis of symmetry will be a vertical line, so the axis of symmetry will be given by the x-coordinate of the vertex only
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