Question

[4_06]Choose the equation below that represents the line passing through the point (-3, -1) with a slope of 4.

Answer 1

help me please

Answer 2

use the "point slope" formula
\[y-y_1=m(x-x_1)\] replace \(x_1\) by \(-3\) and \(y_1\) by \(-1\) and \(m\) by \(4\)

Answer 3

\(\bf \begin{array}{lllll}
&x_1&y_1\\
(&3\quad ,&-1)
\end{array}
\\\quad \\

slope = m= 4
\\ \quad \\

y-y_1=m(x-x_1)\qquad \textit{plug in your values and solve for "y"}\)

Answer 4

hmmm \(\bf \begin{array}{lllll}
&x_1&y_1\\
&(-3\quad ,&-1)
\end{array}
\\\quad \\

slope = m= 4
\\ \quad \\

y-y_1=m(x-x_1)\qquad \textit{plug in your values and solve for "y"}\)

Answer 5

y = -2x - 7
y = -2x +5
y = 2x + 5
y = 2x - 7

here are my choices

Answer 6

@satellite73 then what? i got y-1=4(x-3)

Answer 7

@jdoe0001

Answer 8

\(\bf \begin{array}{lllll}
&x_1&y_1\\
&(-3\quad ,&-1)
\end{array}
\\\quad \\

slope = m= 4
\\ \quad \\

y-y_1=m(x-x_1)\implies y-(-1)=4(x-(-3)\)

Answer 9

then just solve for "y" to get the equation

Answer 10

@jdoe0001 can you jts give the answer?

Answer 11

makes us wonder why you weren't given the answer sheet along with the exercise
do you know why?

Answer 12

ok , i understand. but i donr get it. i tried solving for y and got something ridiculous

Answer 13

well... tis ok... what did you get?

Answer 14

y - 1 = 4(x - 3)

y + 1 = 4(x + 3)

y - 3 = 4(x + 1)

y + 3 = 4(x - 1)

Answer 15

ohhhhhh , it is the first one?

Answer 16

@jdoe0001

Answer 17

hmmm.... those look like choices, rather than your simplification

Answer 18

i didnt have to simplfy , these are my choices?

Answer 19

@jdoe0001

Answer 20

\(\bf \begin{array}{lllll}
&x_1&y_1\\
&(-3\quad ,&-1)
\end{array}
\\\quad \\

slope = m= 4
\\ \quad \\

y-y_1=m(x-x_1)\implies y-(\color{red}{-1})=4(x-(\color{red}{-3}))\)

Answer 21

recall that - times - = +