Question

find the x-and y- intercepts of the line that passes through the given points

Answer 1

(-6,4),(3,-5)

Answer 2

the easiest way to do this is graph it.

but you can also find the equation for it by finding the slope, then plugging it into point slope then solving that to get the slope intercept form of the equation. then make x=0 for the y-intercept and y=0 for x-intercept.

but i will give u a link to the graph to make life easier. give me a sec

Answer 3

i dont understand

Answer 4

um can you give me an example thats confusing so i turn it into an equation but how

Answer 5

first find the slope using this equation:
\[\frac{ y ^{2}-y ^{1} }{ x ^{2}-x ^{1} }\]
then after u find the slope plug in one of the points(doesnt matter which one) and the slope into the point slope form which is:
\[y-y ^{1}=slope(x-x ^{1})\]
after the solve to get the equation that looks like this (slope intercept form):
\[y=mx+b\]and m=slope

Answer 6

ok let me solve it and i will answer you

Answer 7

alrighty :)

Answer 8

i got y=-x+4 so x is 6 and y is 4???

Answer 9

actually the equation would end up being y=-x-2. tell me ur step so i can find ur problem

Answer 10

wait how?

Answer 11

i think i messed up

Answer 12

just type in your steps so i can find ur problem and we can fix it

Answer 13

after i did\[\frac{ y2-y1 }{ x2-x1 }=\frac{ -5-4 }{ 3--6 }=\frac{ -9 }{ 9 }=-1\]

Answer 14

u got the slope correct

Answer 15

then i did y-y1=m(x-x1)
y-4=-1(x+6)
y=-x+4
]then i have to find the x- and y- intercept

Answer 16

i dont know how to do it please help me

Answer 17

when you distribute it should look like this: that would make 6 go back to a negative and also x will be negative to. so then it would be y-4=-x-6
then you would add 4 to both sides and -6+4 is -2