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Perform the indicated operations: (x^2+x-6)/(x^2+4x-12)÷(x+3)/(x-1)
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factor the 2 quadratics... and remember when you divide by a fraction, flip and multiply. then you should see common factors that can be removed.
The answer that I got is: (x-1)/(x+6) after I factored and cancelled. What am I doing wrong? The answer is suppose to be: 1/(x+6)(x-1).
ok... so its \[\frac{(x +3)(x-2)}{(x +6)(x -2)} \times \frac{(x -1)}{(x + 3)}\] well I got the same as you...
Maybe my teacher put the wrong answer then.
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