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Mathematics 18 Online
OpenStudy (anonymous):

find the equation of tangent line to the graph of y=sinx at x="pie"

OpenStudy (anonymous):

Find dy/dx. Sub in x = pi and that's your slope.

OpenStudy (isaiah.feynman):

@witthan1 In case of next time its spelt 'pi'

OpenStudy (isaiah.feynman):

Sorry who gave me a medal? because I don't get a notification for that.

OpenStudy (anonymous):

the deriviative of the sinx is the cosx.....and what a derivative does is let you find the slope at any point....so, if I take the cosine (pi) I get -1, so the slope at Pi is -1.....now we go to the equation y = mx + b, and m is -1....so we have y = -x + b......to find b, we need to plug in the point (Pi, 0) - x = pi, and when I plug Pi into the sine function, I get y = 0....soo.... 0 = -Pi + b, adding Pi to both sides, we get b = Pi. So, da-dum....the equation of the tangent line would be y = -x + Pi...whew, hope you followed this

OpenStudy (jdoe0001):

pie sounds delicious though =)

OpenStudy (anonymous):

pecan

OpenStudy (anonymous):

do we get pie for helping out?

OpenStudy (anonymous):

Lol thanks! |dw:1386193766780:dw|

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