find the equation of tangent line to the graph of y=sinx at x="pie"
Find dy/dx. Sub in x = pi and that's your slope.
@witthan1 In case of next time its spelt 'pi'
Sorry who gave me a medal? because I don't get a notification for that.
the deriviative of the sinx is the cosx.....and what a derivative does is let you find the slope at any point....so, if I take the cosine (pi) I get -1, so the slope at Pi is -1.....now we go to the equation y = mx + b, and m is -1....so we have y = -x + b......to find b, we need to plug in the point (Pi, 0) - x = pi, and when I plug Pi into the sine function, I get y = 0....soo.... 0 = -Pi + b, adding Pi to both sides, we get b = Pi. So, da-dum....the equation of the tangent line would be y = -x + Pi...whew, hope you followed this
pie sounds delicious though =)
pecan
do we get pie for helping out?
Lol thanks! |dw:1386193766780:dw|
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