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Find the equation of the tangent line to the graph of y=sin x at x=4pi
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We are working on the exactly same question somewhere else, this the link use it as a sample to guide you to the answer. http://openstudy.com/study#/updates/529fa1b8e4b01a67794e9131
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Take the derivative of sinx, plug x = 4pi into it for the slope.. Then take a point and the slope back into a slope equation for the answer.
I found the slope and got this equation: y=1x+b but then when I put 4pi into sin it gives me -2E-13. Is this correct so far?
-2E -13 is your calculators way of saying zero
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So the answer is y=1x+4pi ?
seems good to me
Thanks!
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