Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

subtracting a rational function , help ?

OpenStudy (anonymous):

\[\frac{ 3 }{ 2x } -\frac{ 9 }{ 2 } = 6x\]

OpenStudy (agent0smith):

Get common denominators, as you learned yesterday ;)

OpenStudy (anonymous):

but i get confused on as how to get the common denominator when its comes to multiplying/dividing and adding/subtracting :/

OpenStudy (agent0smith):

Well what's missing from the right fraction?

OpenStudy (anonymous):

an x ?

OpenStudy (agent0smith):

So fix that :D

OpenStudy (anonymous):

so what happens to the 6x ?

OpenStudy (anonymous):

do i multiply 6x by 2x since the denominator is 1 ?

OpenStudy (agent0smith):

Leave 6x alone for now

OpenStudy (anonymous):

\[\frac{ 3 }{ 2x } - \frac{ 9x }{ 2x }= 6x\]

OpenStudy (anonymous):

okay so now what ?

OpenStudy (agent0smith):

Do stuff! You know how to subtract them! :P

OpenStudy (anonymous):

well i cant subtract 3 from 9x because theyre not like terms

OpenStudy (agent0smith):

That doesn't mean you can't combine (subtract) the fractions

OpenStudy (anonymous):

3 - 9x = 6x ?

OpenStudy (agent0smith):

No, just put them over a common denominator.

OpenStudy (agent0smith):

That's why you got a common denominator of 2x, remember.

OpenStudy (anonymous):

\[\frac{ 3-9x }{ 2x }\]

OpenStudy (agent0smith):

Correct. It equals 6x. Now, multiply both sides by 2x, to get rid of that denominator.

OpenStudy (anonymous):

3 - 9x = 12^2

OpenStudy (agent0smith):

12x^2? yes.

OpenStudy (anonymous):

oh yeh i forgot the x sowwy , but now its a regular quadratic equation right ?

OpenStudy (agent0smith):

\[\Large 3-9x = 12x^2\]now get it equal to zero, and solve for x. It will be a quadratic.

OpenStudy (agent0smith):

Btw to make it easier, divide *everything* by the common factor of 3.

OpenStudy (anonymous):

\[ 4x^2 + 3x - 1 = 0 \]

OpenStudy (agent0smith):

Awesome, now solve either by factoring or quadratic formula!

OpenStudy (anonymous):

ima try the quadratic formula because i dont like factoring when a has a coefficient greater than 1 :p

OpenStudy (agent0smith):

Yeah it sucks. Start by multiplying the first and last numbers, 4*-1 = -4 find two numbers that multiply to -4 and add up to the middle number 3... which... there aren't any. Screw factoring.

OpenStudy (anonymous):

haha i got x = 1/4 & -1 (:

OpenStudy (agent0smith):

You're right.

OpenStudy (anonymous):

thank you so much (:

OpenStudy (agent0smith):

Welcome as always <3

OpenStudy (agent0smith):

Oh wow it does factor, lol " two numbers that multiply to -4 and add up to the middle number 3" +4 and -1 oops.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!