subtracting a rational function , help ?
\[\frac{ 3 }{ 2x } -\frac{ 9 }{ 2 } = 6x\]
Get common denominators, as you learned yesterday ;)
but i get confused on as how to get the common denominator when its comes to multiplying/dividing and adding/subtracting :/
Well what's missing from the right fraction?
an x ?
So fix that :D
so what happens to the 6x ?
do i multiply 6x by 2x since the denominator is 1 ?
Leave 6x alone for now
\[\frac{ 3 }{ 2x } - \frac{ 9x }{ 2x }= 6x\]
okay so now what ?
Do stuff! You know how to subtract them! :P
well i cant subtract 3 from 9x because theyre not like terms
That doesn't mean you can't combine (subtract) the fractions
3 - 9x = 6x ?
No, just put them over a common denominator.
That's why you got a common denominator of 2x, remember.
\[\frac{ 3-9x }{ 2x }\]
Correct. It equals 6x. Now, multiply both sides by 2x, to get rid of that denominator.
3 - 9x = 12^2
12x^2? yes.
oh yeh i forgot the x sowwy , but now its a regular quadratic equation right ?
\[\Large 3-9x = 12x^2\]now get it equal to zero, and solve for x. It will be a quadratic.
Btw to make it easier, divide *everything* by the common factor of 3.
\[ 4x^2 + 3x - 1 = 0 \]
Awesome, now solve either by factoring or quadratic formula!
ima try the quadratic formula because i dont like factoring when a has a coefficient greater than 1 :p
Yeah it sucks. Start by multiplying the first and last numbers, 4*-1 = -4 find two numbers that multiply to -4 and add up to the middle number 3... which... there aren't any. Screw factoring.
haha i got x = 1/4 & -1 (:
You're right.
thank you so much (:
Welcome as always <3
Oh wow it does factor, lol " two numbers that multiply to -4 and add up to the middle number 3" +4 and -1 oops.
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