Question

Write the equation of the line that passes through (-1, 4) with a slope of -1 in standard form.
-x + 4y = -1
x - 4y = -1
x + y = 3
x - y = -3
Write the equation of the line that passes through (2, 2) and (6, 3) in standard form.
4x + 4y = 6
x + 4y = 12
4x + 4y = -12
x - 4y = -6
Write the equation of the line that passes through (3, 6) and (0, -3) in slope-intercept form.
y = 3x - 6
y = 3x - 3
y = 3x + 3
y = 3x + 6

Answer 1

First

y-y1=m(x-x1)
m=slope
(x,y1)=(-1,4)

Answer 2

put value in formula and tell me what answer.

Answer 3

(x1,y1)=(-1,4)

Answer 4

i dont kno thats y im asking! lol

Answer 5

y-(4)=-1(x-(-1))
y-4=-x-1
y=-x+3
x+y=3

Answer 6

Second
Let (2, 2) and (6, 3) be (x1,y1) & (x2,y2)
First find the slope
m=(y2-y1)/(x2-x1)
m=1/4
Then take any pt (2, 2) or (6, 3)
(y-y1)=m(x-x1)
Then substitute the values of m & x1&y1
x-4y+6=0

Answer 7

can u jus give me the numbers and letters??

Answer 8

well the numbers n answers