Question

I'm trying to solves the system, but I don't know where to start. Here's the given:
(5/x^2) - (2/y^2) + 3 = 0
(3/x^2) - (1/y^2) = 7

Answer 1

\[\frac{ 5 }{ x ^{2} } - \frac{ 2 }{ y ^{2} } +3 = 0\]
\[\frac{ 3 }{ x ^2 } - \frac{ 1 }{ y ^2 } = 7\]

Answer 2

times 2 the 2nd equation, what do you get ?

Answer 3

Oh!
\[\frac{ 6 }{ x ^{2} } + \frac{ 2 }{ y ^{2} } = 14\] ?

Answer 4

(6/x^2) - (2/y^2) = 14

Answer 5

I have it now! Thank you!

Answer 6

Put 1/x^2=a and 1/y^2=b...the equations will turn into linear equation in two variables which you can solve simuntaneously