Question

please help ...Write the equation of the line that is parallel to the line 4x − 3y = −12 and passes through the point (−3, 4)

Answer 1

answer choices are:
y = 4/3x + 8
y = 4/3x + 3
y = -3/4 +8
y = -3/4x +3

Answer 2

for it to be paralell, we don,t really care about the Right Hand Side (RHS) aka -12 so we just bring that line to the origin which gives: 4x-3y=0, then solving for y we get:

y = (4/3)x + c (c is any number dependint on what the intercept is), now just plug in your point (-3,4) we get

4 = (4/3)*(-3) + c ----> 4 = -4 + c ----> c = 8 hence your final awnser is:

y = (4/3)x + 8

have a nice day! :)

Answer 3

wow your smart thanks