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sin2x-sinx=0
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what should we do ? prove it or what ?
To find the zeroes, you may factor out a "sinx" from both go get:\[sinx(sinx-1)=0\] This tells us that the values that make y zero are when sinx=0, and sinx=1 (made sinx alone inside the parenthesis). From our unit circle, sinx=0 at 0 and 2pi. Sinx=1 at pi/2 and 3pi/2. If you need more elaboration, feel free to ask.
i think sin2x = 2sinxcosx not 2sinx
sin2x-sinx=0 2sinxcosx-sinx=0 sinx(2cosx-1)=0 u can find the value of x sinx=0 2cosx-1=0
Mmm, indeed, depends if she meant sin^2(x) or sin(2x)...I believe you're correct in the interpretation, however.
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