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Mathematics 17 Online
OpenStudy (anonymous):

If y=(2x-1)/(3x+1), then (dx)/(dy)= ????

OpenStudy (bibby):

Do you know the quotient rule? u'v -uv'/v^2

OpenStudy (anonymous):

yes

OpenStudy (shamil98):

Use the quotient rule then.

OpenStudy (bibby):

OpenStudy (shamil98):

\[\huge \frac{ (2x-1)dx(3x+1) - (2x-1)(3x+1)dx }{ (3x+1)^2 }\]

OpenStudy (shamil98):

now simplify it..

OpenStudy (anonymous):

5/(3x+1)^2 ????

OpenStudy (bibby):

Let's start with the top. u'v - uv' the derivative of (2x-1) would be 2, right? 2(3x+1) - (2x−1)(3x+1)dx

OpenStudy (anonymous):

yes

OpenStudy (bibby):

what's the derivative of 3x +1?

OpenStudy (anonymous):

3

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