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If y=(2x-1)/(3x+1), then (dx)/(dy)= ????
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Do you know the quotient rule? u'v -uv'/v^2
yes
Use the quotient rule then.
\[\huge \frac{ (2x-1)dx(3x+1) - (2x-1)(3x+1)dx }{ (3x+1)^2 }\]
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now simplify it..
5/(3x+1)^2 ????
Let's start with the top. u'v - uv' the derivative of (2x-1) would be 2, right? 2(3x+1) - (2x−1)(3x+1)dx
yes
what's the derivative of 3x +1?
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