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What are the zeroes of y = x^2 – 2x – 15? –3, –5 3, 5 –3, 5 3, –5 I believe it's D (3, -5)
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y = x^2 – 2x – 15 x^2 – 2x – 15 = 0 (x - 5) (x + 3)
Common mistake, what is the number that will make x - 5 or x + 3 zero?
Hint, -5 -5 = -10 it's not the right answer.
-3, 5?
Yeah, exactly.
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But how does that fit in with factoring?
Look \[0 = (5-5) (5 + 3) = 0 \times 8 = 0 \] \[0 = (-3-5)(-3 + 3) = -8 \times 0 = 0\]
I see my mistake \facepalm thanks!
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