Question

I just want to know if I am going in the right direction with this. I am using AC Method, just factoring it out.

8k^2-6k-9
8k^2-12k+6k-9

4k(2k-3) 3(2k-3)
(2k-3)(4k+3)

Answer 1

I assume that the AC method is factoring by grouping which involves, in this case, finding two numbers that multiply to -72 (that's ac) AND add to -6 (that's b).

Your work looks good to me except for a missing sign.

8k^2-12k+6k-9

4k(2k-3) 3(2k-3) --> should be 4k(2k-3) + 3(2k-3)

Then, you have a common binomial factor of (2k - 3) and get

(2k-3)(4k+3) as you did.

So, put the "+" symbol where it belongs and your work is fine.

Answer 2

Oh god, thank you for pointing that out. I half way through this homework just up and started neglecting to put that in the assignments. Ugh. Studying for finals I am hoping I can remember what 1+1 is by time I'm done. ^^;

Answer 3

Sometimes, that sign will be negative. Let me think up an example.

Answer 4

Try this:

Factor by grouping.

--> 2x² - 5x + 3

Post your work, okay? @Jlynn89