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expand 2x(x-8)^2
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\[\huge 2x(x-8)(x-8)\]
multiply (x-8)(x-8) first then multiply the product by 2x
What would I do in this instance then? (x+2)(x+7)(x-2)
well it's the same thing you don't have to do in any specific order, you can multiply and add in any order and you'll get the same result
Here's what I got... I don't think it's right at all. \[x ^{3}+7x ^{2}-10x-42\]
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is that right?
(x+2)(x+7)(x-2) = (x + 2)(x - 2)(x + 7) = x^2 - 4(x + 7) = x^2(x + 7) - 4(x + 7) = x^3 + 7x^2 - 4x - 28
oh ok! Thank you very much!
Keep in mind difference of squares \((a + b)(a - b) = a^2 - b^2\) And distributive property: \(a(b + c) = ab + ac\)
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