Question

Help me .-.

Answer 1

@RyGuy

Answer 2

perpendicular i think

Answer 3

i wouldnt quote me on it

Answer 4

Oh .-.

Answer 5

@cambrige

Answer 6

sorry :/

Answer 7

It's okay.

Answer 8

check their slopes

Answer 9

u ther girl??

Answer 10

yes.

Answer 11

So first bring both the equations to their standard form.
Ax+By+C=0

Answer 12

then find their slope which is defined as
Slope,m=(-A)/B...get me??

Answer 13

I really didn't wanna do all the work ;-; Lol

Answer 14

u've got to.........Its os.I'll help u but u gotta do it urself!!

Answer 15

its just a 2 second process....

Answer 16

Not for me .-. it'll take me forever .-.

Answer 17

I got the ans the moment I saw the question.not bragging..........I'll walk u thru it...

Answer 18

first write them in their standard form for e.g
the first one can be rewritten as

Answer 19

4x+y-3=0
like the form Ax+By+C=0
here A=4,B=1,C=-3

Answer 20

now u try the second one

Answer 21

Wut... I don't even understand how you got that.

Answer 22

4x+y-3=0
like the form Ax+By+C=0
here A=4,B=1,C=-3..............which part is troubling u??

Answer 23

Nevermind.

Answer 24

The second one is already in the form.

Answer 25

nope the constant is on the other side!!

Answer 26

for the first one slope,m1=(-4)/1=-4

Answer 27

getin me??

Answer 28

How? .-. It's the same damn formula.
4x + y - 3 = 0
and
-2x + 8y = 5
looks like the same formula to me.

Answer 29

-2x+8y=5 is the same formula.............
but not in the standard form whereas 4x + y - 3 = 0 is in the "standard form"

Answer 30

don't be rude!!

Answer 31

I'm not.

Answer 32

did u get what I said??

Answer 33

Not really. LOL

Answer 34

k .......so the answer is perpendicular

Answer 35

Thank you! :)

Answer 36

m1*m2=1 for lines to be perpendicular

Answer 37

;)..ur welcome!!