Question

sin(x)= Tan(x)/Sec(x)

need help with Trig identity

Answer 1

well you are dividing by a fraction on the right hand side... so flip and multiply.

You aslo need to use tan = sin/cos

\[\frac{\tan(x)}{\sec(x)} = \frac{\sin(x)}{\cos(x)} \div \frac{1}{\cos(x)} = \frac{\sin(x)}{\cos(x)} \times \frac{\cos(x)}{1}\]

hope this helps

Answer 2

\(\bf \cfrac{tan(x)}{sec(x)}\implies \cfrac{\frac{sin(x)}{cos(x)}}{\frac{1}{cos(x)}}\) see campbell_st 's line above

Answer 3

sinx =tanx \ secx
tanx =sinx \cos x and secx =1\cosx
\[sinx=\frac{ sinx }{ cosx } \times \cos x \]
sinx =sinx

Answer 4

oooh ok

Answer 5

thanks guys

Answer 6

i see where i messed up, i thought tan(x)=cos(x)/sin(x)

Answer 7

yw