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1. During a medieval siege of a castle, the attacking army uses a trebuchet to hurl heavy stones at the castle walls. If the trebuchet launches the stones with a velocity of +35.0 m/s at an angle of 60.0°, how long does it take the stone to hit the ground? What is the maximum distance that the trebuchet can be from the castle wall to be in range? How high will the stones go? Show all your work

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Help asap?

1.	During a medieval siege of a castle, the attacking army uses a trebuchet to hurl heavy stones at the castle walls. If the trebuchet launches the stones with a velocity of +35.0 m/s at an angle of 60.0°, how long does it take the stone to hit the ground? What is the maximum distance that the trebuchet can be from the castle wall to be in range? How high will the stones go? Show all your work

anonymous · Answer

Get the time by having gravity decrease the vertical component of velocity by -9.8m/s^2.
Height is when this vertical velocity is zero. Double that time for the return trip.

The distance will be the  horizontal velocity times the time. 

v sub y is [35 m/s] sin(60)
v sub x is [35 m/s] cos(60)