Question

convert root(3x) into a polar form?

Answer 1

\(\bf y =\sqrt{3}\quad ?\)

Answer 2

\(\bf y =\sqrt{3x}\quad ?\) rather

Answer 3

y=\[\sqrt{3x}\]

Answer 4

\(\bf y=\sqrt{3x}\\ \quad \\ \quad \\
\textit{recall that}\quad rcos(\theta)=x\qquad rsin(\theta)=y\qquad thus\\ \quad \\
y=\sqrt{3x}\implies y^2=3x\implies [rsin(\theta)]^2=3rcos(\theta)\\ \quad \\
r^2sin^2(\theta)=3rcos(\theta)\implies r=\cfrac{3\cancel{r}cos(\theta)}{\cancel{r}sin^2(\theta)}\)

Answer 5

thanks