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OpenStudy (anonymous):
given that angle A is in quadrant 4, and cosA= 1/3. find cotA?
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OpenStudy (math&ing001):
|dw:1386452575237:dw|
OpenStudy (anonymous):
would it be - sqrt2 over 4?
OpenStudy (campbell_st):
well look it it this way
|dw:1386452958252:dw|
OpenStudy (campbell_st):
|dw:1386453061319:dw|
when you have a
find
tan(A) using the information then take the reciprocal to find cot(A)
OpenStudy (anonymous):
so it would be - sqrt 2 over 4 right?
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OpenStudy (campbell_st):
well
\[a = -2\sqrt{2}\]
and now
\[\tan(A) = -\frac{2\sqrt{2}}{1}\]
find the reciprocal for cot(A)
OpenStudy (campbell_st):
so your answer is correct after the denominator has been rationalised
OpenStudy (anonymous):
oh so it woulbe be 2 sqrt 2 over 4?
OpenStudy (campbell_st):
opps... mucked that up... should be
\[\cot(A) = -\frac{1}{2 \sqrt{2}}\]
rationalising
\[\cot(A) = -\frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}} = - \frac{\sqrt{2}}{4}\]
OpenStudy (anonymous):
got it! thank you so much!
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OpenStudy (campbell_st):
hopefully I didn't confuse you to much
OpenStudy (anonymous):
no i got it :) thanks!
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