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Mathematics 18 Online
OpenStudy (anonymous):

given that angle A is in quadrant 4, and cosA= 1/3. find cotA?

OpenStudy (math&ing001):

|dw:1386452575237:dw|

OpenStudy (anonymous):

would it be - sqrt2 over 4?

OpenStudy (campbell_st):

well look it it this way |dw:1386452958252:dw|

OpenStudy (campbell_st):

|dw:1386453061319:dw| when you have a find tan(A) using the information then take the reciprocal to find cot(A)

OpenStudy (anonymous):

so it would be - sqrt 2 over 4 right?

OpenStudy (campbell_st):

well \[a = -2\sqrt{2}\] and now \[\tan(A) = -\frac{2\sqrt{2}}{1}\] find the reciprocal for cot(A)

OpenStudy (campbell_st):

so your answer is correct after the denominator has been rationalised

OpenStudy (anonymous):

oh so it woulbe be 2 sqrt 2 over 4?

OpenStudy (campbell_st):

opps... mucked that up... should be \[\cot(A) = -\frac{1}{2 \sqrt{2}}\] rationalising \[\cot(A) = -\frac{1}{2\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}} = - \frac{\sqrt{2}}{4}\]

OpenStudy (anonymous):

got it! thank you so much!

OpenStudy (campbell_st):

hopefully I didn't confuse you to much

OpenStudy (anonymous):

no i got it :) thanks!

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