Question

Use partial Fractions to solve inegral

4y/ y^3-y^2+y-1

Answer 1

Hint: y-1 is one of the factors of y^3-y^2+y-1

Answer 2

(y^2+1)(y-1)

I keep trying to solve for A and B

Answer 3

im doing it like Ay+B/9Y^2+1) + C/(y+1)

Answer 4

@satellite73 @Mertsj sorry my brain is stuck now idk y

Answer 5

Try: \[\Large \frac{ 4y }{ (y^2+1)(y-1)} = \frac{ Ay + B }{ y^2+1 } + \frac{ C }{ y-1 }\]

Answer 6

that what I've been using to solve for A and B and C

Answer 7

you have a (y+1) under C. It should be (y-1).

Answer 8

A+C = 0
B-A+4
C-B = 0

Answer 9

B-A = 4. Add all three and you will get C.

Answer 10

A=-2
c=2
b=2