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Simplify x+1/2x^2+5x+3 Divided by 2/2x+3
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\[\frac{ x+1 }{2x ^{2}+5x+3 }\div \frac{ 2 }{ 2x+3 }\]
Factorize \(2x^3+5x+3\) first :)
\[=\frac{ x+1 }{ 2x ^{2}+5x+3 } \times \frac{ 2x+3 }{2 }\]
Factorize \(2x^2+5x+3\) first :)
@kc_kennylau if you multiply by the reciprocal first it allows you to identify a factor that will most likely be cancelled
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you both are confusing me
Just factorize \(2x^2+5x+3\) first
@kc_kennylau so it would be 2x(x+5x+3)
nope it would be \((2x+3)(x+1)\)
@kc_kennylau so then i would write \[\frac{ x+1 }{ (2x+3)(x+1) }\div \frac{ 2 }{ 2x+3 }\]
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