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I could someone explain to me how to solve this (20 sigma notation I=1) 2i
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\[\sum_{i=1}^{20}2i\]?
Yes
Do I factor 2 out of the sum
First??
What this is saying is you add up 2i for i from 1 to 20: 2(1) +2(2) +...+2(19)+2(20) There are two ways to do this: The long way is to add them up... The short way is to use the formula: \[s=\frac{ n(a_1+a_n) }{ 2 }\] Where n is the number of terms, a1 is the first term, and a2 is the last term.
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Don't worry about factoring the 2 out, the equation doesn't depend on the distance between the numbers.
Okay so would I then multiply 2 with n and I with n(n+1)/2
*i
n is the number of terms (20), a1 is the first term (2×1=2), an is the last term (2×20=40)
Oky thank you I got the answer 240 wen I solved it
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