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Mathematics 23 Online
OpenStudy (anonymous):

I could someone explain to me how to solve this (20 sigma notation I=1) 2i

OpenStudy (ddcamp):

\[\sum_{i=1}^{20}2i\]?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Do I factor 2 out of the sum

OpenStudy (anonymous):

First??

OpenStudy (ddcamp):

What this is saying is you add up 2i for i from 1 to 20: 2(1) +2(2) +...+2(19)+2(20) There are two ways to do this: The long way is to add them up... The short way is to use the formula: \[s=\frac{ n(a_1+a_n) }{ 2 }\] Where n is the number of terms, a1 is the first term, and a2 is the last term.

OpenStudy (ddcamp):

Don't worry about factoring the 2 out, the equation doesn't depend on the distance between the numbers.

OpenStudy (anonymous):

Okay so would I then multiply 2 with n and I with n(n+1)/2

OpenStudy (anonymous):

*i

OpenStudy (ddcamp):

n is the number of terms (20), a1 is the first term (2×1=2), an is the last term (2×20=40)

OpenStudy (anonymous):

Oky thank you I got the answer 240 wen I solved it

OpenStudy (anonymous):

*420

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