Suppose that (x, (-24/25)) is a point in quadrant IV lying on the unit circle.

Find x . Write the exact value, not a decimal approximation.
what does this mean? please help me

Question

Suppose that  (x, (-24/25)) is a point in quadrant IV lying on the unit circle.

 Find x . Write the exact value, not a decimal approximation.
what does this mean? please help me

luigi0210 · Answer

I think it means we need to solve.. 
So on the unit circle the points are: (cosx, sinx) right?
So far we have sinx. which is opp/hyp
Now we just need cosx which is adj/hyp:
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So find x, using a^2+b^2+c^2

campbell_st · Answer

well just draw a picture

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luigi0210 · Answer

The x would be better as b..

anonymous · Answer

so -24^2 +x^2 = 25^2?

luigi0210 · Answer

Yes, and that will give us the adj angle we need

anonymous · Answer

so x =7?

luigi0210 · Answer

Yup, so it would be cosx=7/25.. cos/sec are positive in the 4th and 1st quad

anonymous · Answer

so since it says to just find x, that means I should say x = 7  right?

campbell_st · Answer

no, the circle has a radius of 1 unit... hence the name, unit circle

the the value of x is 7/25

hope that makes sense...

luigi0210 · Answer

Uhm, yea.. what campbell said xD

luigi0210 · Answer

Fast typer xD

anonymous · Answer

k thanks you two:D