A (0, 0), B (5, 0), and C (2, 4). These coordinates will be the vertices of a triangle. How would you use the distance formula to determine what kind of triangle this is? Is the triangle equilateral, right, or scalene?
the distance for A and B is 5 as well as the distance for B and C. the distance for A and C is sqrt 20.
Can anyone tell me if I did the problem right ?
The triangle is isosceles, with AC and BC being equal. You would use the distance formula and compare if 2, 3 or none of the sides are the same length, for isosceles, equilateral, and scalene respectively. They would all be similar. 1) Line joining the midpoint of two sides of a triangle is parallel and half the length of the third side. 2) Alternate angles on parallel lines are equal.
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