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Please help!! I honestly have no idea how to do this. \[\sum_{i=1}^{\infty} 6(3)^{i-1}\] find the 7th partial sum
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isnt that a GP?
What's a GP? @divu.mkr
gp is a sequence in which each term have a constant ratio with the next one
in this ques is 3
Yes i understand that I just call that the constiant ratio, ive ever heard it called the gp
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yep.... in this question just take out 6 out of sigma and sum of a gp is a(1-r^n)/(1-r)
I have no idea what youre doing. I was taught that im suppose to do something and plug the information iinto the arithmetic formula Sn=\[s _{n}= (n/2) (a_{1}+a_{n})\]
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