Question

Please help!! I honestly have no idea how to do this. \[\sum_{i=1}^{\infty} 6(3)^{i-1}\] find the 7th partial sum

Answer 1

isnt that a GP?

Answer 2

What's a GP? @divu.mkr

Answer 3

gp is a sequence in which each term have a constant ratio with the next one

Answer 4

in this ques is 3

Answer 5

Yes i understand that I just call that the constiant ratio, ive ever heard it called the gp

Answer 6

yep.... in this question just take out 6 out of sigma and sum of a gp is a(1-r^n)/(1-r)

Answer 7

I have no idea what youre doing. I was taught that im suppose to do something and plug the information iinto the arithmetic formula Sn=\[s _{n}= (n/2) (a_{1}+a_{n})\]