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Mathematics 8 Online
OpenStudy (anonymous):

Let f(x) = ln(x+(1/x)). f'(x) = (x^2 - 1)/ (x^3 + x). Find the x-coordinate of the point(s) on f at which the tangent to f is horizontal.

OpenStudy (anonymous):

horizontal tangent -> slope=0 (x^2 - 1)/ (x^3 + x)=0

OpenStudy (anonymous):

Okay I get that a horizontal tangent means the slope is zero but that doesn't tell me anything.

OpenStudy (anonymous):

the derivative of a function f(x) is the slope of the tangent line touching (x,f(x))

OpenStudy (anonymous):

wait scratch that just figured it out!

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

Thanks so much :)!

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