HEEEELP!! In rabbits black coat colour is dominant over white, short hair is dominant over long. Show Punnett square between heterozygous black with long and a rabbit that is white and is heterozygous for short hair.

Question

jewlzme17 · Answer

do you have letters? like would it  be (BB) and (ww) (SS) and (ll)?

anonymous · Answer

It doesn't say what letters to use... :( I'm sorry

jewlzme17 · Answer

its okay, just give me a min and I will try :)

anonymous · Answer

Okay, thank you :)

jewlzme17 · Answer

okay so i mad up my own and it is CcHhxCcHh
the C represents color and H represent Hair|dw:1386561165171:dw|

anonymous · Answer

How does this work?

jewlzme17 · Answer

Do you know the foil method? well you get the letter and put it togethor so CcHhxCcHh and the do the foil method first inner outer and last to get the top part then it is the same for the bottom and the you cross it, you can look at the chart to see what I mean

blues · Answer

I think @jewlzme17 has the method right - assign notation to the genes and alleles, then work out which combinations are possible and use them to set up the Punnett Square. But I disagree about what the parents' genotypes are...

blues · Answer

It tells you that short is dominant over long and black is dominant over white.

For gene names I picked:

l - long hair
L - short hair
b - white
B - black

It tells you that one parent os heterozygous black and long haired. Because it tells you that it is heterozygous for colour, you know that its two alleles are Bb for that gene. But it tells you that it is long haired, which is a phenotype associated with recessive alleles. For that recessive phenotype to appear, it must have two recessive alleles for coat length.

So the first parent's genotype is Bbll.

The second parent is white and heterozygous for short hair. Because it is white, and white is a recessive phenotype, you know that it must have two recessive genes for colour. So with respect to colour, it's genotype is bb. You are told that it is heterozygous for coat length, so you know it has one dominant and one recessive allele.

The second parent's genotype is bbLl.

Agree?

blues · Answer

The possible gene combinations that the first parent - Bbll - could pass on are Bl Bl bl and bl.

The possible gene combinations that the second parent - bbLl - could pass on are bL bl bL and bl.

Your Punnett Square looks like:

|dw:1386567038000:dw|

All you have to do is interpret the genotypes and figure out what phenotypes are associated with them.